Teacher answer key · Grades 10–12 · about 25 minutes

Answer key: Law of Sines & Law of Cosines Worksheet

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Goal: Use the law of cosines and the law of sines to find missing sides and angles, and discover when two different triangles fit the same measurements.

Connects to Common Core HSG-SRT.D.10 (Prove the laws of sines and cosines and use them to solve problems.); HSG-SRT.D.11 (Understand and apply the law of sines and the law of cosines to find unknown measurements in right and non-right triangles.)

Completed results table

Values are the readouts of the tool (Triangle solver) for each setting.

SettingSide cAngle AAngle BArea
SAS: a = 6, b = 8, C = 60°7.211 units46.102°73.898°20.785 units²
SAS: a = 6, b = 8, C = 90°10 units36.87°53.13°24 units²
SAS: a = 6, b = 8, C = 120°12.166 units25.285°34.715°20.785 units²
SSS: a = 7, b = 8, c = 99 units48.19°58.412°26.833 units²
SSA: a = 7, b = 10, A = 30° (triangle 1)13.559 units30°45.585°33.898 units²
SSA: a = 7, b = 10, A = 30° (triangle 2)3.761 units30°134.415°9.403 units²

Answers

  1. For a = 6, b = 8 and C = 60°, use the law of cosines c² = a² + b² − 2ab cos C to find c by hand. Does your answer match the solver?

    c² = 36 + 64 − 2 × 6 × 8 × cos 60° = 100 − 96 × 0.5 = 52, so c = √52 ≈ 7.211. This matches the solver.

  2. What happens to the law of cosines when C = 90°? Which famous theorem do you get?

    cos 90° = 0, so the last term disappears and c² = a² + b² = 36 + 64 = 100: the Pythagorean theorem. Side c = 10.

  3. As angle C grew from 60° to 90° to 120°, how did side c change? Use the sign of cos C to explain why.

    c grew from 7.211 to 10 to 12.166. When C is acute, cos C is positive, so 2ab cos C is subtracted and c² < a² + b². When C is obtuse, cos C is negative, so the term is added: c² = 100 + 48 = 148 when C = 120°.

  4. In the 7–8–9 triangle, which angle is the largest, and why? Find it with the law of cosines.

    Angle C, because it is opposite the longest side (9). cos C = (7² + 8² − 9²) ÷ (2 × 7 × 8) = 32 ÷ 112 ≈ 0.2857, so C ≈ 73.398°.

  5. The SSA measurements a = 7, b = 10, A = 30° gave two triangles. Use the law of sines to find both possible values of angle B, and explain why there are two.

    sin B = b sin A ÷ a = 10 × 0.5 ÷ 7 ≈ 0.7143. Two angles have this sine: B ≈ 45.585° and B ≈ 180° − 45.585° = 134.415°. Both leave room for angle C (A + B < 180°), so two different triangles fit the same measurements. This is the ambiguous case.

  6. Check the law of sines on the 6–8–60° triangle: calculate a ÷ sin A and c ÷ sin C. What do you notice?

    a ÷ sin A = 6 ÷ sin 46.102° ≈ 8.327 and c ÷ sin C = 7.211 ÷ sin 60° ≈ 8.327. The ratios are equal, as the law of sines says (b ÷ sin B gives 8.327 too).

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